Gravity Force Lab

Objective:
Our objective was to see how mass affects gravitational force. We wanted to see if it positively affected, negatively affected, or had no affect on the gravitational force.

Plan:
We would test this theory by using the force meters that were given to us in class. We would hook them up to the laptop that had logger pro and use that to see how weight had affect on the number of newtons acting on the force meter. We would attach weights to the bottom of the force meter of various weights and then write down in a data table what the newtons were in relation to each differing mass. Once we found that, we would use the information in the data tables to create a graph with the mass that is measured in kilograms on the x-axis and force, measured in newtons on the y-axis. Once the dots are plotted, we would make a line representing the direction of the correlation. We would make this graph by putting the point in Xcel and having the program graph the line and give us the formula that the information would provide.  good

As you can see from the data table, we used differing weights that were, at first, twice as much as the previous, but the last weight is only 0.1 kg larger than the previous because we could not double the previous weight. However, as seen from the graph, there is some sort of correlation between the mass (kg) and the force that is attributed to that mass.
title the graph

VM: As the mass (Kg) increases, the force of gravity (N) increases proportionally. 

MM: Force = (9.8298 N/Kg)mass + 0.0076 N 

Slope: For every kg the force increased 9.8298 N.

Y-int: When mass is at 0, force is at 0.0076 N. 

very good

Claim/Evidence/Conclusion

The force increased proportionally with the increase of mass. The graph shows that each time more weight mass was added to the device, the force of gravity increased with it. There was no decrease with the increase of mass. The difference between mass and weight is a very difficult concept to grasp. In the simplest and most easy to understand terms, mass is how much stuff is in something and weight is the force of gravity that is acting on an object. Subsequently, all things with mass have a corresponding weight. All the graphs are the same because we are all on the planet Earth. All the masses that we measured in relation to force we measured by how much of the Earth's gravity is acting on the object. They each have a different force of gravity, however the force of gravity is proportionate to the mass and therefore is a constant increase in the graph. very good - just state how much the increase is!  And the new equation - This also explains why light and heavy objects all hit the ground at the same time. With the different forces of gravity, their is also a different mass of object. Consequently, objects of larger mass have bigger weight. This mass to weight ratio, if put against another object of a lighter weight and less mass would be proportionate to the other. Thereby, allowing both to fall to the ground, and hit the ground at the same time. excellent!

Dueling Buggies Lab

Objective Statement:
What we are trying to do and accomplish in this lab is to first find the constant velocities of each buggy. Once that is found, we must use those velocities to calculate, from a certain distance apart from each other, where they would meet in centimeters. The distance would be measured centimeters.

Plan:
We decided we would first find the constant speed of the slow buggy and then the speed of them in comparison to the other buggy, the faster buggy. We would do this by starting each one on one side of a meter stick. Then we would see how long it would take in second for the slow buggy to reach the end of the meter stick also known as 100 centimeters. We would use our stopwatch on our phones to calculate the time taken. We would do the same with the faster buggy. Once we did that, we would find that the slower buggy had a constant speed of 18.58 cm/s We got that by taking the distance the buggy traveled, 100 cm, and divided it by the time it took the buggy to get to the end of the 100 cm. As seen on the white board at the end of the post, it took the slower buggy 5.38 seconds to go 100cm. Therefore we took the distance - 100cm and divided it by the time - 5.38 seconds. We did the same thing with the faster buggy which went 100 cm in 2.5 seconds. Therefore we did 100cm/2.5 seconds and found that that buggy would go 40 centimeters in one second.   how did you get that?  what was your time and how did you calculate the speed?  and the constant speed of the faster buggy was calculated as 40 cm/s. We were given that the distance from each buggy would be 140 cm apart. After that we would graph both y=mx+b and find where on the graph the two lines would meet. The x value would then equal at what time in seconds the two would meet and the y value of the intercept would be where on the meter stick they would meet. good

can't see the picture for some reason?? try to fix these....



This would mean that the formula for the fast buggy would be moving at 40 cm per second and would be starting at a position of 0 cm. This would mean that to reach 100 cm would take this buggy 2.5 seconds. However, the end point would be 180 cm. This buggy would be starting at 0cm and moving in a positive direction, and since the opposite buggy is moving in a negative direction towards this buggy, they would meet at a certain point. confusing.....This does not show the intersection of the two points but gives the constant speed of the buggy. The formula being Position = (40 cm/s)time + 0



This would mean that the formula for the slow buggy would be moving at 18.58 cm per second and would be starting at a position of 140 cm. The starting position of the slower buggy would be 180 cm because it is starting on the opposite side of the meter sticks. Therefore, as opposed to the other buggy which starts at 0cm, this buggy would begin in the opposite direction, moving in a negative direction. is it 180 or 140????This would mean that to reach 100 cm, it would take a little less that 4 seconds. This graph does not show and intersection either however the formula being position = (18.57 cm/s)time + 180cm units...?



The graph above shows exactly where the two would intersect, at the point of (3.07,122.91). This would mean that if the buggies were started at the exact same time on either side of 140 cm, they would then intersect at 3.07 seconds and at 122.91 cm. This would mean that the fast buggy would have to travel a full 122.91 centimeters to intersect with the relatively slower constant speed of the other buggy that would only move 57.09 centimeters over the course of 3.07 seconds.good

After testing our theory of whether the buggies would meet at that exact point we found that the buggies did meet at the relative point within the same amount of time. As you can see from the photo below, they met at about 123 cm within the time of 3.71 seconds. This shows that our calculations we very close however our time was a bit off. To improve next time, we can test the constant speed of the buggies multiple times to have a more precise constant speed and therefore more accurate calculation.